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How to Prove a Set of Functions is Closed Under Addition (Example with functions s.t. f(0) = 0)

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Show the Set of Functions such that f(0) = 1 is Not Closed Under Addition

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SOLVED: 3. For the following relations, either prove it is an equivalence relation or give a counterexample and justify why it is not: (a) f Rg in F, the set of all

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