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Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm

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Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm. Draw line BC = 11 cm. Make an angle of 30° at B and 90° at C using a protractor. Bisect angles B and C, and these bisectors will meet at one-point X. Now draw perpendicular bisectors on BX and CX, which will cut the line segment BC on point Y and Z respectively. Now join XY and XZ to get the required triangle XYZ.
It is given that we have to construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm. We have drawn the triangle using a compass and ruler and justified the construction.

CBSE Class 9 Maths Chapter 11 - Constructions Important Questions 2023-24

Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11. - Sarthaks eConnect

NCERT Solutions for Class 9 Maths Chapter 11 Constructions Ex 11.2

Construct a triangle ABC in which B = 60o, C = 45o and the perimeter of the triangle is 11 cm. - uqs32vtii

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Question 4 - Construct triangle XYZ - angle Y = 30, Z = 90, XY + YZ+ZX

construct a triangle xyz in which angle Y is equal to 30 degree angle Z is equal to 90 degree and XY + YZ+

Question 1 - Construct XYZ in which XY = 4.5 cm, YZ = 5 cm and ZX = 6

NCERT Solutions for Class 9 Maths Chapter 11 Constructions, 11.1 & 11.2

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