trigonometry - Proving that $\tan \theta=\cot(90^\circ-\theta)$ when $\theta>90^\circ$ - Mathematics Stack Exchange

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I'm asked to prove $\tan \theta=\cot (90-\theta)$ So $\tan \theta =\frac{a}{b}=\cot(90^\circ-\theta)$ But what if $\theta>90?$

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trigonometry - Why do trigonometric ratios work for all values of $ heta$, while it is initially stated to be true only for $ heta<90°$? - Mathematics Stack Exchange

33 Prove that ( frac { cot ( 90 - theta ) } { tan theta } + frac

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If [math] extrm{cosec } heta = rac{p+q}{p-q}[/math] then [math

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prove tht :cot(90-theta) / tan theta + cosec(90-theta)sin theta / tan(90- theta) =sec^2 theta.

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